PPT Slide
Let’s now tackle a problem where you know
what molarity you want and how much solution
you want but you need to know how much mass
to measure out. Actually, I do this all the time
in the lab. Remember all those solutions that you
use in experiments this year? I do this calculation
all the time when I’m the one making up the
solutions --- no, I don’t have any “chemistry elves”
Needed: 100 mL of a .227 M solution of NaCl
First, we need to isolate the “unknown” on one
side of the equation so that
(M) (#L) (Mol. Wt.) = # g