PPT Slide

If 3.52 grams of H2 is allowed to react with

11.1 grams of oxygen, find the mass of water

produced.

2 H2 + 1 O2 => 2 H2O

3.52 g H2 * 1 mole H2 * 2 mole H2O

2.02 g 2 mole H2

* 18.0 g H2O

1 mole

= 31.4 g H2O

11.1 g * 1 mole O2 * 2 mole H2O * 18.0 g

32.0 g 1 mole O2 1 mole

=12.5 g H2O

Excess

reactant

Limiting

reactant